Respuesta :
Answer:
The value of the Discriminant is D=0 in the given quadratic equation .
The value of the discriminant D=0 mean that the number of real number solutions in the equation has double real roots
Step-by-step explanation:
Given quadratic equation is [tex]-2x^2=-8x+8[/tex]
To find : The value of the discriminant .
[tex]-2x^2=-8x+8[/tex]
[tex]-2x^2+8x-8=0[/tex]
Multiplying by "-" on both sides
[tex]2x^2-8x+8=0[/tex]
Now comparing the above quadratic equation in the standard form of quadratic equation [tex]ax^2+bx +c = 0[/tex] we get.
The values of , a = 2, b= -8, and c = 8
By Discriminant formula:
[tex]D = b^2-4ac[/tex]
Substituting the values in the formula
[tex]D=(-8)^2-4(2)(8)[/tex]
[tex]=8^2-64[/tex]
[tex]=64-64[/tex]
[tex]=0[/tex]
∴ D=0
We know that if the discriminant D= 0, it has double real roots.
